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5x^2-376x+2640=0
a = 5; b = -376; c = +2640;
Δ = b2-4ac
Δ = -3762-4·5·2640
Δ = 88576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{88576}=\sqrt{256*346}=\sqrt{256}*\sqrt{346}=16\sqrt{346}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-376)-16\sqrt{346}}{2*5}=\frac{376-16\sqrt{346}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-376)+16\sqrt{346}}{2*5}=\frac{376+16\sqrt{346}}{10} $
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